Sqrt(x)
Leetcode problem 69; Difficulty: Easy
Problem Statement
Given a non-negative integer x, compute and return the square root of x.
Since the return type is an integer, the decimal digits are truncated, and only the integer part of the result is returned.
Note: You are not allowed to use any built-in exponent function or operator, such as pow(x, 0.5) or x ** 0.5.
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).
Return the running sum of nums.
Constraints:
0 <= x <= 2<sup>31</sup> - 1
Example 1:
Input: x = 4
Output: 2
Example 2:
Input: x = 8
Output: 2
Explanation:
The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
Example 3:
Input: nums = [3,1,2,10,1]
Output: [3,4,6,16,17]
Submitted Solution
The implemented solution received the following rating on Leetcode:
